x/4-x^2-8x/4x-5=7/4

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Solution for x/4-x^2-8x/4x-5=7/4 equation: 


x in (-oo:+oo)

x/4-x^2-(((8*x)/4)*x)-5 = 7/4 // - 7/4

x/4-x^2-(((8*x)/4)*x)-(7/4)-5 = 0

x/4-x^2-2*x^2-7/4-5 = 0

1/4*x-3*x^2-27/4 = 0

DELTA = (1/4)^2-(-27/4*(-3)*4)

DELTA = -1295/16

DELTA < 0

x belongs to the empty set

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